Integrand size = 24, antiderivative size = 87 \[ \int \frac {\sqrt {a+b x^2}}{\sqrt {c-d x^2}} \, dx=\frac {\sqrt {c} \sqrt {a+b x^2} \sqrt {1-\frac {d x^2}{c}} E\left (\arcsin \left (\frac {\sqrt {d} x}{\sqrt {c}}\right )|-\frac {b c}{a d}\right )}{\sqrt {d} \sqrt {1+\frac {b x^2}{a}} \sqrt {c-d x^2}} \]
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Time = 0.03 (sec) , antiderivative size = 87, normalized size of antiderivative = 1.00, number of steps used = 3, number of rules used = 3, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.125, Rules used = {438, 437, 435} \[ \int \frac {\sqrt {a+b x^2}}{\sqrt {c-d x^2}} \, dx=\frac {\sqrt {c} \sqrt {a+b x^2} \sqrt {1-\frac {d x^2}{c}} E\left (\arcsin \left (\frac {\sqrt {d} x}{\sqrt {c}}\right )|-\frac {b c}{a d}\right )}{\sqrt {d} \sqrt {\frac {b x^2}{a}+1} \sqrt {c-d x^2}} \]
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Rule 435
Rule 437
Rule 438
Rubi steps \begin{align*} \text {integral}& = \frac {\sqrt {1-\frac {d x^2}{c}} \int \frac {\sqrt {a+b x^2}}{\sqrt {1-\frac {d x^2}{c}}} \, dx}{\sqrt {c-d x^2}} \\ & = \frac {\left (\sqrt {a+b x^2} \sqrt {1-\frac {d x^2}{c}}\right ) \int \frac {\sqrt {1+\frac {b x^2}{a}}}{\sqrt {1-\frac {d x^2}{c}}} \, dx}{\sqrt {1+\frac {b x^2}{a}} \sqrt {c-d x^2}} \\ & = \frac {\sqrt {c} \sqrt {a+b x^2} \sqrt {1-\frac {d x^2}{c}} E\left (\sin ^{-1}\left (\frac {\sqrt {d} x}{\sqrt {c}}\right )|-\frac {b c}{a d}\right )}{\sqrt {d} \sqrt {1+\frac {b x^2}{a}} \sqrt {c-d x^2}} \\ \end{align*}
Time = 0.74 (sec) , antiderivative size = 87, normalized size of antiderivative = 1.00 \[ \int \frac {\sqrt {a+b x^2}}{\sqrt {c-d x^2}} \, dx=\frac {\sqrt {a+b x^2} \sqrt {\frac {c-d x^2}{c}} E\left (\arcsin \left (\sqrt {\frac {d}{c}} x\right )|-\frac {b c}{a d}\right )}{\sqrt {\frac {d}{c}} \sqrt {\frac {a+b x^2}{a}} \sqrt {c-d x^2}} \]
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Time = 2.44 (sec) , antiderivative size = 104, normalized size of antiderivative = 1.20
method | result | size |
default | \(\frac {\sqrt {b \,x^{2}+a}\, \sqrt {-d \,x^{2}+c}\, a \sqrt {\frac {-d \,x^{2}+c}{c}}\, \sqrt {\frac {b \,x^{2}+a}{a}}\, E\left (x \sqrt {\frac {d}{c}}, \sqrt {-\frac {b c}{a d}}\right )}{\left (-b d \,x^{4}-a d \,x^{2}+c b \,x^{2}+a c \right ) \sqrt {\frac {d}{c}}}\) | \(104\) |
elliptic | \(\frac {\sqrt {\left (b \,x^{2}+a \right ) \left (-d \,x^{2}+c \right )}\, \left (\frac {a \sqrt {1-\frac {d \,x^{2}}{c}}\, \sqrt {1+\frac {b \,x^{2}}{a}}\, F\left (x \sqrt {\frac {d}{c}}, \sqrt {-1-\frac {-a d +b c}{a d}}\right )}{\sqrt {\frac {d}{c}}\, \sqrt {-b d \,x^{4}-a d \,x^{2}+c b \,x^{2}+a c}}-\frac {a \sqrt {1-\frac {d \,x^{2}}{c}}\, \sqrt {1+\frac {b \,x^{2}}{a}}\, \left (F\left (x \sqrt {\frac {d}{c}}, \sqrt {-1-\frac {-a d +b c}{a d}}\right )-E\left (x \sqrt {\frac {d}{c}}, \sqrt {-1-\frac {-a d +b c}{a d}}\right )\right )}{\sqrt {\frac {d}{c}}\, \sqrt {-b d \,x^{4}-a d \,x^{2}+c b \,x^{2}+a c}}\right )}{\sqrt {b \,x^{2}+a}\, \sqrt {-d \,x^{2}+c}}\) | \(254\) |
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none
Time = 0.09 (sec) , antiderivative size = 130, normalized size of antiderivative = 1.49 \[ \int \frac {\sqrt {a+b x^2}}{\sqrt {c-d x^2}} \, dx=-\frac {\sqrt {-b d} b c^{2} x \sqrt {\frac {c}{d}} E(\arcsin \left (\frac {\sqrt {\frac {c}{d}}}{x}\right )\,|\,-\frac {a d}{b c}) + \sqrt {b x^{2} + a} \sqrt {-d x^{2} + c} b c d - {\left (b c^{2} + a d^{2}\right )} \sqrt {-b d} x \sqrt {\frac {c}{d}} F(\arcsin \left (\frac {\sqrt {\frac {c}{d}}}{x}\right )\,|\,-\frac {a d}{b c})}{b c d^{2} x} \]
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\[ \int \frac {\sqrt {a+b x^2}}{\sqrt {c-d x^2}} \, dx=\int \frac {\sqrt {a + b x^{2}}}{\sqrt {c - d x^{2}}}\, dx \]
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\[ \int \frac {\sqrt {a+b x^2}}{\sqrt {c-d x^2}} \, dx=\int { \frac {\sqrt {b x^{2} + a}}{\sqrt {-d x^{2} + c}} \,d x } \]
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\[ \int \frac {\sqrt {a+b x^2}}{\sqrt {c-d x^2}} \, dx=\int { \frac {\sqrt {b x^{2} + a}}{\sqrt {-d x^{2} + c}} \,d x } \]
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Timed out. \[ \int \frac {\sqrt {a+b x^2}}{\sqrt {c-d x^2}} \, dx=\int \frac {\sqrt {b\,x^2+a}}{\sqrt {c-d\,x^2}} \,d x \]
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